Getting names from formulas and formulas from names

Sometimes figuring out the charge on an ion can be a little challenging (and fun), so take a look at how to name FeNH₄(SO₄)₂. I show you earlier the sulfate ion has a 2– charge, and from the formula you can see that there are two of these ions. Therefore, you have a total of four negative charges. The ammonium ion has a 1+ charge, so you can figure out the charge on the iron cation:

Because you have a 4– charge for the sulfates and a 1+ for the ammonium, the iron must be a 3+ to make the compound neutral. So the iron is in the iron (III), or ferric, oxidation state. You can name the compound:

FeNH₄(SO₄)₂: Iron (III) ammonium sulfate, or ferricammonium sulfate And finally, if you have the name, you can derive the formulaand the charge on the ions. For example, suppose that you’re given the name cuprous oxide. You know that the cuprous ion is Cu⁺ and the oxide ion is O^2–. Applying the crisscross rule (from the earlier section “Using the crisscross rule”), you get the following formula:

Cuprous oxide: Cu₂O

مواضيع ذات صلة

كيمياء القصدير

تطبيقات الطبقات الثنائية الهيدروكسيد

تطبيقات عملية التبادل الأيوني

مواد التبادل الأيوني Ion exchanger

ظاهرة التبادل الايوني Ion Exchange

تاريخ التبادل الايوني Ion Exchange History

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طرائق تقدير النحاس

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طرائق تقدير النيكل

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