Read More
Date: 27-6-2019
1304
Date: 23-6-2019
1234
Date: 24-6-2017
1468
|
We have just seen that the bonding molecular orbital is lower energy and promotes the formation of a covalent bond, while the antibonding molecular orbital is higher energy with a node of zero electron density between the atoms that destabilizes the formation of a covalent bond. We can evaluate the strength of a covalent bond by determining its bond order.
Bond order = 1/2 (# of electrons in bonding MOs – # of electrons in antibonding MOs)
Bond-order values can be whole numbers, fractions, or zero. These values correspond to the valence bond model, so a bond order of 1 is equal to a single bond, and 2 is equal to a double bond. A value of zero means that there is no bond present, and the atoms exist separately.
Example 1: Determine the bond order of the hydrogen molecule.
Solution
Bond order = 1/2 (# of electrons in bonding MOs – # of electrons in antibonding MOs)
Bond order = 1/2 (2 – 0) = 1
Therefore there is a single bond in the hydrogen molecule.
|
|
دراسة تحدد أفضل 4 وجبات صحية.. وأخطرها
|
|
|
|
|
العتبة العباسية تستعدّ لتكريم عددٍ من الطالبات المرتديات للعباءة الزينبية في جامعات كركوك
|
|
|