Isothermal Expansion of an Ideal Gas

If we have one mole of an ideal gas in our cylinder, and keep the temperature constant at a temperature T₁ , then the gas will obey the ideal gas equation.
pV = RT₁ = constant .........(1)
Thus the equation for the pressure of an ideal gas during an isothermal expansion is
p = constant/V .......(2)
and we see that the pressure decreases as 1/V. This decrease is shown in the pV diagram of Figure (1).

Figure 1: In the isothermal expansion of an ideal gas, we have pV = constant. Thus the pressure decreases as 1/V.

مواضيع ذات صلة

الديناميكا الحرارية الجزيئية

توزيع بولتزمان

العلاقات بين الخواص

القانون الثالث للديناميكا الحرارية

الطاقة الحرة

القانون الثاني للديناميكا الحرارية

القانون الأول للديناميكا الحرارية

Order and entropy

Irreversibility

The Clausius-Clapeyron equation

Internal energy

Entropy